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Category. Discipline. Disciplines. Organisations. Law. Law Pamphlet. Law. Legislation.Q:
How to export ES6 List to JSON?
How to export ES6 list to JSON string without.map and.forEach?
for example:
[
‘A’,
‘B’,
‘C’
]
to JSON
‘[A,B,C]’
A:
You can use the spread operator or the Object.values method, for example:
const result = [
‘A’,
‘B’,
‘C’
].map(value => JSON.stringify(value))
or
const result = Object.values(yourArray)
A:
You can use the Array.map method and JSON.stringify:
The map method creates a new array with the results of calling a
provided function on every element in this array.
‘[A,B,C]’ is valid JSON.
JSON.stringify(‘[A,B,C]’) // ‘[A,B,C]’
The spread syntax in ES6 will return an empty array as it is not valid JSON.
JSON.stringify([]) // “[]”
Try this:
const arr = [‘a’,’b’,’c’];
const json = JSON.stringify(arr);
console.log(json);
A:
ES6 map use lambda expression so it will be easy to convert.
[1,2,3,4].map(number=> number.toString());
//[1,2,3,4]
const json = [1,2,3,4].map(number=> number.toString());
//'[1,2,3,4]’
Q:
Use GridView to display two columns side by
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https://ello.co/8ulbrittur-sa/post/jruq3auroffgxpdyjhg9oq
https://colab.research.google.com/drive/15N9DxUrHbcohSiJ8GEZHgTkg844dT2M3
I want to combine them like this:
baremodehonorariosdelcolegiodeabogadosdecadiz ((Adda Abogados Cdiz) Mapeadas).(comu)
I’m doing it like this:
f = open(‘test.txt’)
f1 = open(‘test1.txt’)
f2 = open(‘test2.txt’)
for x in f:
for y in f1:
for z in f2:
try:
print(x, ‘
‘, y, ‘
‘, z)
except ValueError:
pass
break
break
break
This is the output:
baremodehonorariosdelcolegiodeabogadosdecadiz (Adda Abogados Cdiz) Mapeadas).(comu)
baremodehonorariosdelcolegiodeabogadosdecadiz
((Adda Abogados Cdiz) Mapeadas).(comu)
((Adda Abogados Cdiz) Mapeadas).(comu)
I want the output to be:
baremodehonorariosdelcolegiodeabogadosdecadiz (Adda Abogados Cdiz) Mapeadas).(comu)
((Adda Abogados Cdiz) Mapeadas).(comu)
((Adda Abogados Cdiz) Mapeadas).(comu)
How can I achieve this, please?
A:
This is a tricky problem because when you iterate over two or more files, file1 sometimes become the final value of each iteration, so all the other operations become irrelevant. If you’re lucky, Python never returns a file1 during the iteration, but even if Python is lucky, it sometimes returns a file1 multiple times. You can use a trick to solve the problem. Try using a temporary list as the argument to each iteration:
import tempfile
from itertools
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