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Q:
Proof of Pythagoras Theorem
I was thinking about this problem:
“Let $x$ and $y$ be real numbers. Prove or disprove the following statements:
a) If $y$ is an integer, then so is $x+y$
b) If $x$ is an integer, then so is $x+y$
c) If $y$ is a rational number, then $x+y$ is also rational”
The question seems to suggest there is a proof of the Pythagoras Theorem by reduction.
I proved statements a) and c) as follows:
a) $\sqrt{a^2+(b-k)^2} = \sqrt{a^2+b^2-(2ak)} = \sqrt{(a+b-2k)^2 – 2k^2}$ (we can assume $0\leq k \leq a$, otherwise we would have $a\leq b$ and the statement is true).
b) Let $q$ be a real number such that $q=r-s$. Then $r+s = q+2s = q+2r-2s = q+2q-2s = 2q-2s = 2r-2s$.
Of course there are infinitely many rationals between two rationals (or any two real numbers). I think my proofs for a) and b) imply that if $x$ is an integer then $x+y$ is also an integer and
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