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Need help with a Proof of a Certain Theorem in Ring Theory
Let $R$ be a commutative ring, $S$ a subring of $R$, $T\subset S$, $T_0$ an ideal of $T$, and $S/T$ the ring of all elements of $S$ whose image in $S/T$ is zero. In the case when $T_0=T$, it can be shown that $S/T$ is an integral domain. I have an assignment to complete where I have to show that if $S/T$ is an integral domain, $T\subset S$ is a maximal ideal of $R$, and $S/T$ is not an integral domain, then $R$ is not a domain. This was a step in a proof of a theorem I had to prove. I am going to reproduce my assignment below with the questions I have remaining for an assignment of a different nature. I am not looking for a complete solution as that is overwhelming, but I would appreciate some help in pointing me in the right direction.
Theorem: If $R$ is a commutative ring, $T\subset S$ is a maximal ideal of $R$, $S/T$ is an integral domain, and $T$ is not closed under multiplication, then $S/T$ is not an integral domain.
Given the context of the assignment, the ring $R$ is either some field $\mathbb{F}$ or is a commutative ring with an identity.
Proof of Theorem:
Assume towards a contradiction that $S/T$ is an integral domain and that $T$ is not closed under multiplication. Let $x, y$ be nonzero elements in $S$. We know that $S/T$ is an integral domain, so we can find an $f\in R[X]$ such that $f(x), f(y)\in T_0$. This implies that $f(x)y=0$ in $R$, i.e.
